A glass slab of 10cm thickness is placed above a small coin. Another thin glass container with water upto a height of 10cm is placed above the glass slab. If the coin is looked from above normally,where will it be seen?
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Answer:
RI=apparent depthreal depth
Substituting,34=apparentdepth12
Therefore, apparent depth=412×3=9
The height by which it appears to be raised is 12−9=3cm
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