Question

A glass slab of dimension 10 cm x 10 cm x 4 cm and weight 8 N rests
with its sides 10 cm x 10 cm in contact with the top of the table. The
slab is now tilted and allowed to rest on the surface on the side that
measures 10 cm x 4 cm. Calculate the pressure exerted in each case.
Will the pressure increase, decrease or remain the same when the slab
is titled?


PLEASE ANSWER.​

Answer 1

Answer:

Cross-sectional area A=10×10 cm

2

=10

−2

m

2

Heat flowing per second Q=

l

KAΔT

⟹ Q=

0.01

0.8×10

−2

×80

=36 J/s..

Answer 2

Answer:

pls convert to decimals on your own

Explanation:

1st case P =F/A = 8/100= 1/25N

2ND CASE 8/40 = 1/5N

THE PRESSURE WILL INCREASE WHEN IT IS TILTED BECAUSE SMALLER THE AREA GREATER THE PRESSURE FOR THE SANE FORCE APPLIED.