A glass sphere has a radius 6 cm and an air bubble is trapped inside it is at a distance of 1 cm
from the centre. Determine the apparent position of the bubble when viewed from
(refractive index of glass = 1.5) nearest surface.
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Explanation:
Solution:
Given,
Refractive index of the glass sphere, μ1 = 1.5
Refractive index of the air, μ2 = 1
object distance from the surface, u = - ( 6 - 1 ) = - 5cm, as the bubble is 1cm from its centre.
Radiusof the sphere, R=−6cm
Using the formula for refraction on the curved surface, we get
=> μ2 / v − μ1 /u =( μ2 − μ1 )/ R
=> 1/v - 1.5/-5 = ( 1.5 - 1 )/-6
=> v = - 2.60m.
Hence the air bubble appear at a distance of 2.6cm from the survace to the observer.
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