Question

a glass stopper weights 40 grams in air . when immersed in water, it appeared to weight 25 grams . find the relative density of the stopper​

Answer 1

Answer:

I think 10 gram is the relative density

Answer 2

Answer:

Given, Mass of glass stopper in air

= 40 g

Weight of glass stopper in air = m×g

= 40 × 9.8 = 392 N

Mass of glass stopper in water = 25 g

Weight of glass stopper in water = m × g

= 25 × 9.8 = 245 N

Weight of water displaced =

Weight of glass stopper in air - Weight

of glass stopper in water

=> Weight of water displaced

= 392 N - 245 N

=>Weight of water displaced = 147 N

Relative Density of glass stopper =

Weight of glass stopper in air / weight

of water displaced

=> R. D. of glass stopped = 392 N / 147 N

=> R. D of glass stopper = 2.67

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