Question

a glass stopper weights 40 grams in air. when immersed in water , it apperests weight 25 grams . find the relative density of the stopper​

Answer 1

10 grams maybe i think so

Answer 2

Answer:

Given,

Mass of glass stopper in air = 40 g

Weight of glass stopper in air

= m × g = 40 × 9.8 = 392 N

Mass of glass stopper in water = 25 g

Weight of glass stopper in water

= m × g = 25 × 9.8 = 245 N

Weight of water displaced =

Weight of glass stopper in air - Weight

of glass stopper in water

=> Weight of water displaced

= 392 N - 245 N

=> Weight of water displaced = 147 N

Relative Density of glass stopper =

Weight of glass stopper in air /Weight

of water displaced

=> R. D. of glass stopped = 392 N / 147 N

=> R. D of glass stopper = 2.67

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