Physics, asked by KMANISH2337, 9 months ago

A glass tube of length 150 cm is

completely filled with water. A vibrating

tuning fork of frequency 340Hz is kept

over the mouth of the tube and water

is drained out slowly from the bottom

of the tube. If velocity of sound in air

is 340 m/s then the total number of

resonance that occur will be

1) 2

2) 3

3) 1

4) 5

Answers

Answered by singhrandhir82042
2

Answer:

2=3

Explanation:

please mark me as the brainleast answer

Answered by mindfulmaisel
0

The total number of resonance that will occur will be 2) 3

Length of the glass tube (l) = 150 cm

Frequency of the tuning fork (n) = 340 Hz

Velocity of sound in air (v) = 340 m/s

In the first case,

The glass tube is fully filled with water.

So, it will act as closed organ pipe.

∴ Wavelength of the wave will be (λ) = l/4

                                                             = 150/4 cm

                                                             = 15/40 m

∴ Frequency produced will be = v/λ

                                                 = (340×40)/ 15

                                                 ≅ 906

So, number of resonance frequency will be = 906/340

                                                      = 2.82

                                                       ≅ 2

The number of frequency will be 2

In second case,

When water is out, it will act as open organ pipe.

Wavelength = l/2

                    = 0.75 m

Frequency will be = 340/0.75

                             = 453.33

Number of resonance frequency will be = 453.33/340

                                                                   = 1.33

                                                                   ≅ 1

The number of frequency will be 1

So, the number of frequency will be = (2+1) = 3

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