A glass tube of length 150 cm is
completely filled with water. A vibrating
tuning fork of frequency 340Hz is kept
over the mouth of the tube and water
is drained out slowly from the bottom
of the tube. If velocity of sound in air
is 340 m/s then the total number of
resonance that occur will be
1) 2
2) 3
3) 1
4) 5
Answers
Answer:
2=3
Explanation:
please mark me as the brainleast answer
The total number of resonance that will occur will be 2) 3
Length of the glass tube (l) = 150 cm
Frequency of the tuning fork (n) = 340 Hz
Velocity of sound in air (v) = 340 m/s
In the first case,
The glass tube is fully filled with water.
So, it will act as closed organ pipe.
∴ Wavelength of the wave will be (λ) = l/4
= 150/4 cm
= 15/40 m
∴ Frequency produced will be = v/λ
= (340×40)/ 15
≅ 906
So, number of resonance frequency will be = 906/340
= 2.82
≅ 2
The number of frequency will be 2
In second case,
When water is out, it will act as open organ pipe.
Wavelength = l/2
= 0.75 m
Frequency will be = 340/0.75
= 453.33
Number of resonance frequency will be = 453.33/340
= 1.33
≅ 1
The number of frequency will be 1
So, the number of frequency will be = (2+1) = 3