A glass tube, sealed at both ends, is 100 cm long. It lies horizontally with the middle 10 cm containing mercury. The two ends of the tube contain air at 27°C and at a pressure 76 cm of mercury. The air column on one side is maintained at 0°C and the other side is maintained at 127°C. Calculate the length of the air column on the cooler side. Neglect the changes in the volume of mercury and of the glass.
Answers
Answered by
3
Thus the length of air column is 36.51 cm
Explanation:
Here 2 L + 10 = 100 cm
2 L= 90 cm
L = 45 cm
- Applying combined gas equation to part 1 of the tube.
((45 A)Po / 300) = ((45−x)A x P1 / 273)
(P 1) = (273×45×Po/300(45−x))
- Applying combined gas equation to part 2 of the tube.
((45 A)Po /300) = ((45+x) A x P2 /400)
(P2) = (400×45×Po/ 300 (45+x))
Now
(P1) = (P2)
(273 × 45×Po/ 300(45−x)) = (400×45×Po /300(45+x)
(45 × 273 / 45−x) = (400×45/45+x)
(45−x)400=(45+x)273
(18000−400 x)=(12285+273 x)
(400+273)x = 18000−12285
x = 8.49
P1 = (273 × 45 × 76/300 × 36.51)
=85.25 cm of Hg
L-x = 45 - 8.49 = 36.51 cm
Thus the length of air column is 36.51 cm.
Also learn more
What is pressure .Explain with example ?
https://brainly.in/question/1601855
Similar questions