A glouber salt na2so4.h20 calculate mass required which contains 180g of water of crystalization
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Hi there
- Mass of water of crystallization = 180 g
Therefore moles of h2o= 180/18 = 10 moles
USING STOICHIOMETRY
- 1 mole of h20 combines with 1 mole of na2so4
- Therefore 10 moles will combine with 10 moles of na2so4
Therefore moles of na2so4= 10 moles
Therefore mass of na2so4=10*(46+32+64)
=10*142
=1420gm
=1kg42gm
Thank you
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