Question

A glycerin drop of mass 10^-3g with charge equal to 2e is balanced in an external field. Calculate the strength of electric field, if the field is sufficient enough to hold the drop

Answer 1

Explanation:

F=mg

qE=mg

2×1.6×10^-19 ×E=10^-3×10

3.2×10^-19×E=10^-2

E=10^-2/3.2×10^-19

E=0.33×10^-17N/c

E=3.3×10^-18N/c

Answer 2

Answer:

Explanation:

Solution :

⏭ Given:

✏ mass of water drop = 0.001 kg

✏ Charge on water drop = 1.6 ×

⏭ To Find:

✏ Electric field strength required to support water drop in air.

⏭ Concept:

✏ This question is completely based on concept of Force equilibrium.

⏭ Formula:

✏ Electrical Force = Weight Force

⏭ Calculation:

Direction : upward