Question

A gm molecule of gas at 127℃expands isothermally until it's volume is doubled. Find the amount of workdone and hear absorbed.
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Answer 1

Hey mate,

We know,

W = 2.303*R*T*log(V2/V1)

Now we know,

R = 8.3 J/mol-k

T = 127

= 400 k

So, putting in the required values,

W = 2.303*8.3*400*log(2/1)

On solving,

W = 2.3*10^3 J

The heat absorbed will be = 2.3*10^3/4.2

= 548 cal

Hope this helps you out!

Answer 2

here is your answer_____