Question

A goat is tied to a pole in the ground with a rope 14m long. find the area of the ground covered by the goat.
Please answer soon.​

Answer 1

Answer:

hence area of circle=pi*r*r

Area covered by goat=(pi*r*r)/4

So area=((22/7)*7*7)/4)=38.5 sq.m5 years agoHelpfull: Yes(4) No(1)actually area of square is a^2 but why we are using area of circle?6 years agoHelpfull: Yes(3) No(2)((22/7)*49)/4=38.55 years agoHelpfull: Yes(2) No(2)formula :a/360*(pi*r*r) where a is angle made by rope when tied to a corner of square

90/360*22/7*7*7=38.5m^25 years agoHelpfull: Yes(2) No(2)38.5, (90/360)(22/7)*7*74 years agoHelpfull: Yes(0) No(0)38.5 sq m

Area covered=(pi*r^2)/4

r=74 years agoHelpfull: Yes(0) No(0)sise of square=12

rope size=7

area graze by goat=3.14*7*7/4=38.54 years agoHelpfull: Yes(0) No(0)so basically we have to find the area of the circle whose diameter is the length of the rope = 7m

Therefore radius = 7/2 = 3.5m

therefore area of the circle = Pi * (radius)^2 = Pi * (radius) * (radius) = 3.14 * 3.5 *3.5 = 38.5 sq.m4 years agoHelpfull: Yes(0) No(0)since length of rope=7m

so it can graze only area covered by radius 7m./4

since,within this square only 1/4th area is present

so....area=22/7*7*7/4

=38.5 m24 years agoHelpfull: Yes(0) No(0)a.38.5sq.m

(pi*r^2)/4

38.5

4 years agoHelpfull: Yes(0) No(0)area=pi*r*r/4

=3.142*7*7/4

=38.5 sqm4 years agoHelpfull: Yes(0) No(0)Why can't it grace outside the plot as in rectangular barn problems..............?4 years agoHelpfull: Yes(0) No(0)

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