Question

A goblet contains 2 red marbles, 6 green marbles and 4 blue marbles. if we choose a marble, then another marble without putting the first one back in the goblet, what is the probability that the first marble will be green and the second will be green as well?

Answer 1

Answer:

Step-by-step explanation:

p(getting red marbles)=2/12=1/6

p(getting green marble)=6/12=1/2

p(getting blue marble)=4/12=1/3

Thanks

Answer 2

Answer:

Your question is best and most difficult question in my life

Please mark as brainlist