Question

A goblet contains 3 red balls, 2 green balls, and 6 blue balls. If we choose a ball, then another ball without putting the first one back in the goblet, what is the probability that the first ball will be red and the second will be blue?

Answer 1

Step-by-step explanation:

pe in first case = 3/11

pe in second case = 3/5

Answer 2

Answer:

9/55

Step-by-step explanation: