Question

A godown is in the form of cuboid of measure 60m *40m* 30m.how many cubical boxes can be stored in it if side of I box is 10cm ​

Answer 1

Answer:

90,000

Step-by-step explanation:

this is the correct answer for ur questions

Answer 2

$\large\underline{\sf{Solution-}}$

Given that, A godown is in the form of cuboid of measure 60m × 40m × 30m.

It means,

• Length of Cuboid, l = 60 m

• Breadth of Cuboid, b = 40 m

• Height of Cuboid, h = 30 m

We know, Volume of cuboid of length l, breadth b and height h, is given by

$\boxed{ \rm{ \: \: Volume_{(Cuboid)} \: = \: l \: \times \: b \: \times \: h \: \: }}$

So,

$\rm \: Volume_{(Godown)} \: = \: 60 \times 40 \times 30$

$\rm\implies \: \boxed{ \rm{ \:\: Volume_{(Godown)} = 72000 \: {m}^{3} \: \: \: }} - - - (1)$

Now, Further given that

• Side of cubical box, a = 10 cm = 0.1 m

We know, Volume of cube of edge a units is given by

$\boxed{ \rm{ \:Volume_{(Cube)} \: = \: {a}^{3} \: \: }}$

So,

$\rm \: Volume_{(Cubical \: box)} = {(0.1)}^{3}$

$\bf\implies \:Volume_{(Cubical \: box)} \: = \: \dfrac{1}{1000} \: {m}^{3}$

Let assume that n number of cubical boxes of side 10 cm can be stored in godown.

Thus,

$\rm\implies \:n \times Volume_{(Cubical \: box)} = Volume_{(Godown)}$

$\rm \: n \times \dfrac{1}{1000} = 72000$

$\rm\implies \:\boxed{ \rm{ \:n \: = \: 72000000 \: \: }}$

$\rule{190pt}{2pt}$

Additional information :-

$\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{CSA_{(cylinder)} = 2\pi \: rh}\\ \\ \bigstar \: \bf{Volume_{(cylinder)} = \pi {r}^{2} h}\\ \\ \bigstar \: \bf{TSA_{(cylinder)} = 2\pi \: r(r + h)}\\ \\ \bigstar \: \bf{CSA_{(cone)} = \pi \: r \: l}\\ \\ \bigstar \: \bf{TSA_{(cone)} = \pi \: r \: (l + r)}\\ \\ \bigstar \: \bf{Volume_{(sphere)} = \dfrac{4}{3}\pi {r}^{3} }\\ \\ \bigstar \: \bf{Volume_{(cube)} = {(side)}^{3} }\\ \\ \bigstar \: \bf{CSA_{(cube)} = 4 {(side)}^{2} }\\ \\ \bigstar \: \bf{TSA_{(cube)} = 6 {(side)}^{2} }\\ \\ \bigstar \: \bf{Volume_{(cuboid)} = lbh}\\ \\ \bigstar \: \bf{CSA_{(cuboid)} = 2(l + b)h}\\ \\ \bigstar \: \bf{TSA_{(cuboid)} = 2(lb +bh+hl )}\\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}$