Question

A godown is in the form of cuboid of measure 60m *40m* 30m.how many cubical boxes can be stored in it if side of I box is 10cm​

Answer 1

$\huge\orange{Answer:-}$

Volume of one box = 1/1000 m³

Volume of godown = 60 × 40 × 30 = 72000 m³

Number of boxes that can be stored in the godown= Volume of the godown/Volume of one box

= 60 × 40 × 30/1/1000

= 72000000

Hence the number of cuboidal boxes that can be stored in the godown is 72000000.

I hope you have understood the ans yaar

Answer 2

Answer:

Given :-

• A godown is in the form of cuboid of measure 60 m × 40 m × 30 m.
• Side of cube is 10 cm.

To Find :-

• How many cubical boxes can be stored.

Formula Used :-

$\clubsuit$ Volume Of Cuboid Formula :

$\small \bigstar \: \: \sf\boxed{\bold{\pink{Volume_{(Cuboid)} =\: Length \times Breadth \times Height}}}\: \: \: \bigstar$

$\clubsuit$ Volume Of Cube Formula :

$\bigstar \: \: \sf\boxed{\bold{\pink{Volume_{(Cube)} =\: (Side)^3}}}\: \: \: \bigstar$

Solution :-

First, we have to find the volume of godown :

Given :

• Length = 60 m
• Breadth = 40 m
• Height = 30 m

According to the question by using the formula we get,

$\small \implies \sf\bold{\blue{Volume_{(Cuboid)} =\: Length \times Breadth \times Height}}$

$\implies \sf Volume_{(Cuboid)} =\: 60\: m \times 40\: m \times 30$

$\implies \sf Volume_{(Cuboid)} =\: 2400\: m^2 \times 30\: m$

$\implies \sf\bold{\green{Volume_{(Cuboid)} =\: 72000\: m^3}}$

Now, we have to find the volume of cubical box :

Given :-

$\leadsto \sf Side =\: 10\: cm =\: \dfrac{1}{10}\: m =\: \sf\bold{0.1\: m}$

According to the question by using the formula we get,

$\implies \sf\bold{\blue{Volume_{(Cube)} =\: (Side)^3}}$

$\implies \sf Volume_{(Cube)} =\: (0.1\: m)^3$

$\implies \sf Volume_{(Cube)} =\: 0.1\: m \times 0.1\: m \times 0.1\: m$

$\implies \sf Volume_{(Cube)} =\: 0.01\: m^2 \times 0.1\: m$

$\implies \sf\bold{\green{Volume_{(Cube)} =\: 0.001\: m^3}}$

Now, we have to find how many cubical boxes can be stored :

Given :

• Volume of Cuboid = 72000 m³
• Volume of Cube = 0.001 m³

According to the question :

$\small \implies \sf\bold{\blue{Number\: of\: Boxes =\: \dfrac{Volume_{(Cuboid)}}{Volume_{(Cube)}}}}$

$\implies \sf Number\: of\: Boxes =\: \dfrac{72000\: \cancel{m^3}}{0.001\: \cancel{m^3}}$

$\implies \sf Number\: of\: Boxes =\: \dfrac{72000}{0.001}$

$\implies \sf\bold{\red{Number\: of\: Boxes =\: 72000000}}$

$\small \sf\bold{\purple{\underline{\therefore\: 72000000\: cubical\: boxes\: can\: be\: stored\: .}}}$

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