Question

и A Golb ce The position of qt The time of weight hung vertically spring stretches is att. The weight is then palled down 37 and released. Find weight at any damping ferie numerically equal to 15 times is interesus speed is örlingiile molien oscilsiory damped, over damped esa critically damped?​

Answer 1

Answer:

Since the spring obeys Hooke's law, thus F=kx, or K=

x

F

=

2×10

−2

4×9.8

=19.6×10

2

Thus, work done can be written as stored potential energy=

2

1

kx

2

=

2

1

19.6×10

2

×(0.05)

2

=2.45J