A gold biscuit of dimension 5.9mm×3.2mm×3cm was used to form a hollow box of thickness 2mm if the external length and width of the box are 2cm and 1.5cm find the height of the box
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total surface area of biscuit = l× b× h
= 5.9 ×3.2 × 3
= 56.64
total surface area of hollow blox = 2 pie Rh
= 2×22÷7×2×1.5
= 18.85
chughmeghna2:
we want height
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0
Answer:
4 cm
Step-by-step explanation:
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