Math, asked by jer71, 11 months ago

A gold biscuit of dimensions 5.9cm×3.2cm×0.3cm was used to form a hollow box of thickness 0.2cm if the external length and width of the box are 2cm and 1.5cm find the height of the box

Answers

Answered by amitnrw
10

External Height of the Box = 4 cm  if 5.9cm×3.2cm×0.3cm was used to form a hollow box of thickness 0.2cm with external length and width 2cm and 1.5cm

Step-by-step explanation:

A gold biscuit of dimensions 5.9cm×3.2cm×0.3cm

=> Volume of Gold Biscuit = 5.9 * 3.2 * 0.3  cm³

= 5.664 cm³

hollow box of thickness 0.2cm

external length and width of the box are 2cm and 1.5cm

Let Say Height  = H cm

External Volume =  2 * 1.5 * H  = 3H cm³

Internal Volume = ( 2 - 2 * 0.2)(1.5 - 2 *0.2)(H - 2 * 0.2)

= 1.6 * 1.1 * (H - 0.4)

= 1.76H  - 0.704 cm³

3H  - (1.76H  - 0.704)  = 5.664

=> 1.24H  = 4.96

=> H = 4  cm

External Height of the Box = 4 cm

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