Question

A gold biscuit weighing 11 kg contained only 82% gold and the rest copper.
If it was alloyed with another gold biscuit and the resulting alloy had a mass
of 28 kg and contained 90% gold, then find the percentage of gold in the
second biscuit.​

Answer 1

Answer:

Explanation:

First weight is 11 kg

Second weight is 28kg

Gold of first one is 11*82/100=9.02kg

Gold in second one is 28*90/100=25.2kg

Change in weight is 28-11 =17 kg

8/100of x Is 17

The percentage of gold in second biscuit is 87.5%

Answer 2

Explanation:

I hope it helps you.

Please mark me as a brainleist