Physics, asked by knightwolf, 1 year ago

a gold ornament weight 100 g in air and weight only 80 g in water.then relative density of gold is

Answers

Answered by manuboy
1
Weight difference = 150-100 = 50 N = Buoyant force of water. Buoyant Force in water(Fb) = density of water x g x volume of body(Vb). 50 = 1000 x 9.81 x Vb. Vb = 50/ 9810 cubic meter.
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