Question

A gold ring was sold for rupees 7200 at a loss of 12% find its cost price​

Answer 1

$\huge\mathbb{SOLUTION:-}$

$\sf\underline{\blue{\:\:\:\:\: Given:-\:\:\:\:\:}}$

$\sf\bullet S.P\:of\:ring=7200\\ \\ \sf\bullet Loss\%=12\%\\ \\ \sf\bullet C.P=x$

Now

$\bf\underline{\underline{\red{A.T.Q:-}}}$

$\sf\implies x-\dfrac{12x}{100}=7200\\ \\ \sf\implies \dfrac{100x-12x}{100}=7200\\ \\ \sf\implies 88x=7200\times 100\\ \\ \sf\implies x=\dfrac{7200\times 100}{88}\\ \\ \sf\implies x=81.8181\times 100\\ \\ \sf\implies x=8181.81$

$\boxed{\sf{\dag{\:\:C.P\:of\:Gold\:ring=8181.81\: rupee}}}$

Answer 2

$\huge\bold\green{Question}$

A gold ring was sold for rupees 7200 at a loss of 12% find its cost price

$\huge\bold\green{Answer}$

According to the question we have given :-

•°• Selling Price of ring = 7200

•°• Loss percentage = 12%

•°• Cost Price = x

$\begin{lgathered}\tt = x-\dfrac{12x}{100}=7200\\ \\ \tt = \dfrac{100x-12x}{100}=7200\\ \\ \tt = 88x=7200\times 100\\ \\ \tt = x=\dfrac{7200\times 100}{88}\\ \\ \tt = x=81.8181\times 100\\ \\ \tt = x=8181.81\end{lgathered}$

Hence , the required Cost Price of ring is Rs. 8181.81