A gold sample contain 80percent of gold and rest cooper. How many atom of gold are present in 1 gram sample of gold
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Answer:
Meaning 197 g of Gold contains 6.02 x 10∧23 atoms of Gold (Avogadro's No.)
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Answer:
Relative Atomic Mass of Gold = 197
Meaning 197 g of Gold contains 6.02 x 10∧23 atoms of Gold (Avogadro's No.)
Mass of gold in the sample = 90% x 1 g = 0.9 g
If 197 g =6.02 x 10∧23 atoms
∴ 0.9 g = (0.9 x 6.02 x 10∧23) ÷ 197
= 2.75 x 10^21 atoms
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