A gold sample contains 90% of gold and rest is copper. How many atoms of gold are present in 1g of this sample of gold?
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Relative Atomic Mass of Gold = 197
Meaning 197 g of Gold contains 6.02 x 10∧23 atoms of Gold (Avogadro's No.)
Mass of gold in the sample = 90% x 1 g = 0.9 g
If 197 g ≡ 6.02 x 10∧23 atoms
∴ 0.9 g ≡ (0.9 x 6.02 x 10∧23) ÷ 197
≡ 2.75 x 10∧21 atoms
Meaning 197 g of Gold contains 6.02 x 10∧23 atoms of Gold (Avogadro's No.)
Mass of gold in the sample = 90% x 1 g = 0.9 g
If 197 g ≡ 6.02 x 10∧23 atoms
∴ 0.9 g ≡ (0.9 x 6.02 x 10∧23) ÷ 197
≡ 2.75 x 10∧21 atoms
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