A gold wire is in the form of rectangle whose lenght and breath 30 and 20 cm respecteively. It is reband
in the form of circle. Find the
radius of circle.
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Answered by
0
Answer:
When wire is in the form of rectangle-
Length of rectangle (l)=40cm
Breadth of rectangle (b)=26cm
Perimeter of rectangle =2(l+b)
⇒ Perimeter of rectangle =2(40+26)=132cm
Area enclosed by the rectangle (A
1
)=l×b
⇒A
1
=40×26=1040cm
2
When the wire is in the form of circle-
Perimeter of circle will be equal to perimeter of rectangle.
∴ Perimeter of circle =132 cm
⇒2πr=132
⇒r=
2
132
×
22
7
=21cm
Thus the radius of circle is $421 \; cm$$
Now,
Area enclosed by the circle (A
2
)=πr
2
⇒A
2
=
7
22
×(21)
2
=1386cm
2
∵A
2
>A
1
∴A
2
−A
1
=1386−1040=346cm
2
Hence the circle encloses more area than rectangle by 346cm
2
.
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0
Answer:
Correct answer
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