Physics, asked by Anonymous, 6 months ago

A golf ball accelerates of a tee at \frac{15m}{s^2} changing its velocity from \frac{0m}{s} to \frac{15m}{s}.How long did the golf ball accelerates?​

Answers

Answered by Anonymous
41

Given

A golf ball accelerates off a tee at 15 m/s² changing its velocity from 0 m/s to 50 m/s down

To Find

How long did it take the golf ball to accelerate

Solution

We know that

Equation of motion

\sf \longrightarrow v=u+at</p><p>

Here

u = initial velocity

v = final velocity

a = acceleration

t = time

Units

u = metres per second (m/s)

v = metres per second (m/s)

a = metres per second squared (m/s²)

t = seconds (s)

According to the question

We are asked to find how long did it take the golf ball to accelerate

Therefore

We must find "t"

Hence

\sf \longrightarrow t=\dfrac{v-u}{a}</p><p>

Given that

A golf ball accelerates off a tee at 15 m/s² changing its velocity from 0 m/s to 50 m/s down

Hence

u = 0 m/s

v = 50 m/s

a = 15 m/s²

Substituting the values

We get

\sf \longrightarrow t=\dfrac{50-0}{15}  \: s

\sf \longrightarrow t=\dfrac{50}{15} \ s

On further simplification

We get

\sf \longrightarrow t=3.333 \ s</p><p>

Therefore

\sf \longrightarrow t \approx 3.3 \ s</p><p>

Hence

  • Time taken by the golf ball to accelerate = 3.33 seconds

Answered by ItzDeadDeal
28

Answer:

Given :

Acceleration of Golf Ball (a) = 15 m/s²

Velocity of ball changes from 0 m/s to 50 m/s

To Find :

Time taken by golf ball to accelerate

Explanation :

The velocity of the ball changes from 0 m/s to 50 m/s, it means that the ball was initially at rest and the initial velocity of the ball will be taken as 0 m/s. Where are finally velocity of ball was 50 m/s ,So final velocity is 50 m/s. Acceleration of the ball is given as 15 m/s² .

We, will be using here Kinematics Equations, we can find time taken by ball to accelerate by using 1st equation of Motion or Kinematics

</p><p>\bigstar \: \: \boxed{\sf{v \: = \: u \: + \: at}</p><p> </p><p>}

Where,

v is final velocity

u is initial velocity

a is acceleration

t is time interval

Solution :

Use 1st equation of motion :

 \red{\begin{gathered}\implies \sf{v = \: u \: + \: at} \\ \\ \implies \sf{v \: - \: u \: = \: at} \\ \\ \implies \sf{t \: = \: \dfrac{v \: - \: u}{a}} \\ \\ \implies \sf{t \: = \: \dfrac{50 \: - \: 0}{15}} \\ \\ \implies \sf{t \: = \: \dfrac{50}{15}} \\ \\ \implies \sf{t \: = \: 3. \overline{3} }\end{gathered} }</p><p>

\therefore \sf{ Time \:  taken \:  by \:  golf  \: ball  \: to \:  accelerate is}  \: \sf{3. \overline{3} \: s}</p><p> |

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