Question

A golf ball accelerates off a tee at 15m/s2, changing its velocity from 0m/s to 50 m/s down the fairway. How long did it take the golf ball to accelerate?​

Answer 1

Given:

• Acceleration, a = 15 m/s²

• initial velocity,u = 0 m/s

• Final velocity,v = 50 m/s

To be calculated :

Calculate the time taken by the golf ball to accelerate?

Formula used:

v = u+ at

Solution:

★ According to the First equation of motion, we have :

v = u + at

☆ Substituting the values in the First equation of motion ,we get

⇒ 50 = 0 + 15 × t

⇒ 50 = 0 + 15t

⇒ 15t = 50

⇒ t = 50/15

⇒ t = 3.3 s ( approx )

Thus, the time taken by the golf ball is 3.3 seconds

Answer 2

Given :

• Acceleration of Golf Ball (a) = 15 m/s²
• Velocity of ball changes from 0 m/s to 50 m/s

To Find :

• Time taken by golf ball to accelerate

Explanation :

The velocity of the ball changes from 0 m/s to 50 m/s, it means that the ball was initially at rest and the initial velocity of the ball will be taken as 0 m/s. Where are finally velocity of ball was 50 m/s ,So final velocity is 50 m/s. Acceleration of the ball is given as 15 m/s² .

We, will be using here Kinematics Equations, we can find time taken by ball to accelerate by using 1st equation of Motion or Kinematics

$\bigstar \: \: \boxed{\sf{v \: = \: u \: + \: at}}$

Where,

• v is final velocity
• u is initial velocity
• a is acceleration
• t is time interval

Solution :

Use 1st equation of motion :

$\implies \sf{v = \: u \: + \: at} \\ \\ \implies \sf{v \: - \: u \: = \: at} \\ \\ \implies \sf{t \: = \: \dfrac{v \: - \: u}{a}} \\ \\ \implies \sf{t \: = \: \dfrac{50 \: - \: 0}{15}} \\ \\ \implies \sf{t \: = \: \dfrac{50}{15}} \\ \\ \implies \sf{t \: = \: 3. \overline{3} }$

$\therefore$ Time taken by golf ball to accelerate is $\sf{3. \overline{3} \: s}$