Question

A golf ball at rest is hit by a club, such that the force acts on the ball for 0.5 s. if the ball has a mass of 50 g and covers a distanced of 50 m in 2 seconds. Find the magnitude of force.​

Answer 1

Answer:

C

600 N

Impulse P=change in momentum .

Now Vf=−20 ,V1=10 because the direction has reversed .

P=m(Vf−V1)=−0.2×30=−6Ns

Average force =timeImpulse=.016=600N