Question

A golf ball in Projected with a velocity of 40√2m/s at an angle of 45°,Speed of the ball after 2s, will be (ģ- 10 m/s^2)
a) 40 m/s b) 20✓5 m/s
c) 60m/s d) 20√2m/s​

Answer 1

Answer:

mark me as brainliest answer and thanks me for the reply

Explanation:

Use Heisenberg's uncertainty principle.

For example [Δx=

4πmΔv

h

]

Here, Δx is the uncertainty in the position.

Δv is the uncertainty in velocity

m is the mass of Particle.

Given,m=40g=0.04kg

Δv=2%ofv=2×

100

45

=0.9m/s

h=6.626×10

−34

J.s

Now,Δx=

(4×3.14×0.04×0.9)

6.626×10

−34

=1.4654×10

−33

m

So, the correct option is C