Question

A golf ball is hit with an initial velocity of 30 m/s [55°]. What is the ball’s maximum range and height?

Answer 1

Answer:

R = 84.572 m ~ 84.6 m

Explanation:

Using formula: {v(square)sin2X}/g

v or u = initial velocity (30 m/s)

x = angle of trajectory or inclination (55°)

g= 10 m/s(square)

R = Maximum range

R = { (30^2)sin(2×55°) } / 10

= { 900× sin(110°) } / 10

sin(110°) = 0.939

= (900×0.939)/10

= 845.72/10

R = 84.572 m