Question

A golf ball is projected at an angle of 300 with horizontal at a speed of 10 m/s. The angle made by line joining point of projection with the point of maximum height is
a) Tan-1(2/√3)
b) Tan-1(√3)
c) Tan-1(1/√3)
d) Tan-1(1/2√3)

Answer 1

Answer:

Given : u=20

3

m/s θ=60

o

Horizontal component of velocity initially u

x

=u cos60=20

3

×

2

1

=10

3

m/s

Since, there is no acceleration in horizontal direction. So horizontal component of velocity remains the same all the time.

Final horizontal component of velocity v

x

=u

x

=10

3

m/s

Final velocity makes an angle 30

o

with horizontal.

So, vertical component of final velocity v

y

=u

x

tan30=10

3

×

3

1

=10

Initial vertical comonent of velocity u

y

=usin60=20

3

×

2

3

=30 m/s

Using v

y

=u

y

−gt

∴ 10=30−10t

⟹ t=2 s