Physics, asked by akshi7904, 6 hours ago

A golf ball that is initially travelling at 25m/s hits a sand trap and slows down with accelaretion of -20m/s^2. Find its displacement after 2.0s.

Answers

Answered by 229kapilnagra
5

Answer:

10 m is the right answer

Explanation:

please mark as brainliest

Answered by syedfakhrealam72
2

Answer:

the answer 10 m is incomplete.

Explanation:

Remember this question has a trick that they are not asking for distance, rather they require displacement; which is distance along with direction.

The direction of the displacement and velocity vector is simply the same as the direction that an object is moving.

Moreover, When the object moves to another position, its displacement is the second position minus the first position. The word displacement implies we keep track of which way the movement occurs. In one dimension the direction is indicated by the sign: negative if to the left and positive if to the right.

SOLUTION:

From second equation of motion

⇒  S = vit +1/2 at2

Putting the values

⇒  S = 25 x 2 + 1/2 x -20 x  22

⇒  S = 50 -10x 4

⇒  S = 50 – 40

⇒  S = 10 m along the motion of object……………… (Required Answer)

RESULT:

So, its displacement is 10 m along the motion of the golf ball.

Attachments:
Similar questions