Question

A golf ball undergoing the projectile motion, the magnitude of the initial velocity and elevation angle are v , q.
Find the curvature of the starting point 0.

Answer 1

Answer:

v^2/gcos(q)

Explanation:

Curvature=(velocity)^2/acceleration perpendicular to the motion.

R=v^2/gcos(q)

Answer 2

When the particle having the curved path, centripetal force acting on them.

• The motion along the curve, means a trajectory or projectile is there.
• If the centripetal force is there which means there is going to have the m mass of the projectile and g the gravity.
• Also the velocity of the projectile but along it going to have component that is the horizontal component.
• There will be an  angle let be Ф.
• Therefore the curvature at starting point be
• R=(ucosФ)²/g