Question

A golfer hits a ball at rest such that the contact between the ball and the golf stick is for 0.1 second if the golf ball covers a linear distance of 400 metre in 2 seconds find the magnitude of force applied mass of golf ball is 50 g​

Answer 1

Answer:

:) Answer:

The magnitude of the force applied in the golf ball is 100 N .

:) Given:

Contact between golf stick and the golf ball is :

= 0.1 second

Distance covered by the golf ball :

= 400 meter

Time taken to travel the golf ball at the distance of 400 m :

= 2 seconds

Mass of the golf ball :

= 50 g or 0.05 kg

:) To find:

The magnitude of force applied of the golf ball .

:) Taken:

F = M×A

Where,

F = Magnitude of force

M = Mass of the golf ball

A = Acceleration

So , first find the acceleration use this formula :

▪︎First uniform velocity:

v = d÷t

Where,

v = Uniform velocity

d = Distance

t = Time taken

▪︎Then find acceleration:

Where,

v = u + at

v = Final velocity

u = initial velocity

a = Acceleration

t = Time taken

:) Concept:

After finding the acceleration of the golf ball then find the magnitude of the golf ball ...

:) Solution:

First , initial velocity:

Taken , u = d÷t

>> u = d÷t

>> u = 400m ÷ 2 second

>> u = 200 m/s

The , acceleration:

Taken , v = u+at

>> v = u+at

>> 200 m/s = 0+0(0.1s)

>> a = 200 m/s÷0.1s

>> a = 2000 m/s²

Now , find the magnitude of force of the golf ball:

Taken , F = M×A

>> F = M×A

>> F = 0.05 kg×2000 m/s²

>> F = 100 N

:) Answer:

So , the magnitude of the golf ball is 100 N .

:) Extra information:

Formula to find acceleration:

$\bold{A = \frac{V1-V}{T}}$

Where,

A = Acceleration

V1 = Final velocity

V = Initial velocity

T = Time taken

Formula to find mass:

M = F/A

Where,

M = Mass

F = Force

A = Acceleration

HOPE IT HELPS YOU

Answer 2

Answer:

The magnitude of the force applied in the golf ball is 100 N .

:) Given:

Contact between golf stick and the golf ball is :

= 0.1 second

Distance covered by the golf ball :

= 400 meter

Time taken to travel the golf ball at the distance of 400 m :

= 2 seconds

Mass of the golf ball :

= 50 g or 0.05 kg

:) To find:

The magnitude of force applied of the golf ball .

:) Taken:

F = M×A

Where,

F = Magnitude of force

M = Mass of the golf ball

A = Acceleration

So , first find the acceleration use this formula :

▪︎First uniform velocity:

v = d÷t

Where,

v = Uniform velocity

d = Distance

t = Time taken

▪︎Then find acceleration:

Where,

v = u + at

v = Final velocity

u = initial velocity

a = Acceleration

t = Time taken

:) Concept:

After finding the acceleration of the golf ball then find the magnitude of the golf ball ...

:) Solution:

First , initial velocity:

Taken , u = d÷t

>> u = d÷t

>> u = 400m ÷ 2 second

>> u = 200 m/s

The , acceleration:

Taken , v = u+at

>> v = u+at

>> 200 m/s = 0+0(0.1s)

>> a = 200 m/s÷0.1s

>> a = 2000 m/s²

Now , find the magnitude of force of the golf ball:

Taken , F = M×A

>> F = M×A

>> F = 0.05 kg×2000 m/s²

>> F = 100 N

:) Answer:

So , the magnitude of the golf ball is 100 N .

:) Extra information:

Formula to find acceleration:

\bold{A = \frac{V1-V}{T}}A=

T

V1−V

Where,

A = Acceleration

V1 = Final velocity

V = Initial velocity

T = Time taken

Formula to find mass:

M = F/A

Where,

M = Mass

F = Force

A = Acceleration

HOPE IT HELPS YOU