Question

a golfer hits a ball at rest such that the contact between the ball in the golf stick is for 0.1 seconds if the Golf ball cover the linear distance of 400 m in 2 seconds find the magnitude of the force applied mass of the Golf ball is 50 grams

Answer 1

HEY BUDDY

..............................................................................

HERE IS YOUR SOLUTION

given linear distance covered is 400 m in 2 second

so v=400/2 =200m/s

using v = u + at

initial velocity u=0

v=at

200=a×0.1

a=2000 m/s^2

Force = Mass × acceleration

F=0.05×2000

100 N

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Answer 2

Answer:

10N

Explanation:

given,

initial velocity=0

time(t)=0.1sec

s=400m in 25s

F=?

m=50×10-³Kg

F=m×a

s=ut+1/2×at²

400=0+1/2×a(2)²

800=4a

a=800/4=200m/sec

F=50×10–³×200

=5×10×10–³×2×10²

=10⁴–³

=10N

one thing 10–³ these type of numbers or powers like 10power -3 like..tq.