Question

A goods train of 50m long is moving with speed 54km/h .A man is sitting in a passenger train which is moving with 18km/h with same direction. In how many second the goods train crosses the man sitting in a passenger train?

Answer 1

Answer:

Step-by-step explanation:

Total discovered by the length of both trains

=50m+75m

and, Their relative speed in same direction

= 68−50=18 km/hr  

∴(Speed subtracted in same direction)  

then, the time to cross other will be

=125 m/sec18 kms

=125×1818×5m/sec  

{∴1km/h=518m/s}

=25 seconds