A goods train of 50m long is moving with speed 54km/h .A man is sitting in a passenger train which is moving with 18km/h with same direction. In how many second the goods train crosses the man sitting in a passenger train?
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Answer:
Step-by-step explanation:
Total discovered by the length of both trains
=50m+75m
and, Their relative speed in same direction
= 68−50=18 km/hr
∴(Speed subtracted in same direction)
then, the time to cross other will be
=125 m/sec18 kms
=125×1818×5m/sec
{∴1km/h=518m/s}
=25 seconds
labbu98:
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