Question

A got 36% of the maximum marks and failed by 6 marks and b got 42% maximum marks which are 18 above the pass marks . Find the maximum marks and also pass percentage ?

Answer 1

This is the correct answer ..Hope it helps

Answer 2

Answer:

Maximum marks is 400 and pass % is 37.5%

Step-by-step explanation:

Let the maximum marks be x

A got 36% of the maximum marks

So, A got marks = 0.36x

B got 42% marks

B got marks = 0.42x

A failed by 6 marks and B got 18 above pass marks

So, $0.36x+6=0.42 x -18$

$24=0.06x$

$\frac{24}{0.06}=x$

$400=x$

So, passing marks = 0.36x+6=0.36(400)+6=150

Pass% = $\frac{150}{400} \times 100= 37.5\%$

Hence maximum marks is 400 and pass % is 37.5%