Question

A got married 8 years ago. Today her age is 9/7 times her age at the time of her marriage. At present her daughter's age is 1/6 of her age . What was her daughter's age 3 years ago?

Answer 1

Answer

Let her present age = x

Age when she got married = x - 8

According to question, the equation formed:

9/7 times her age during marriage = her present age

=> 9/7(x - 8) = x

Solve this formed equation further:

=> 9x - 72 = 7x

=> 2x = 72

=> x = 36 years

Daughter's age = 1/6 of mother's age

= 1/6 × 36

= 6 years

Before 3 years = 6 - 3 = 3 years

Answer 2

Answer: 3 years

Step by step explanation:

Let "A's" age be x years.

Thus, present age = x + 8 years.

.°. From the given condition,

» (x + 8) = (9/7)x

» 7x + 56 = 9x

» 2x = 56

• » x = 28

Present age = x + 8 = 28 + 8 = 36

Hence, A's present age is 36 yrs.

Now, Daughter's age = 1/6 × Present age of A

= 1/6 × 36

= 6

Thus, Present age of daughter is 6 yrs.

To find : Daughter's age Three yrs ago

.°. Daughter's age 3 yrs ago

= (6 - 3) = 3 years.

Thus, Daughter's age 3 years ago was 3 years.