Question

A graduated cylinder has a mass of 50 g when empty. When 30 mL of water is added, it has a mass of 120 g. If a rock is added to the graduated cylinder, the level rises to 75 ml and the total mass is now 250 g. What is the density of the rock?

Answer 1

We're asked to find the density of the rock, given some mass and volume information.

We're given that the mass of the system before the rock was added was

120

g

. The mass after the rock was added was

250

g

, so the rock's mass is

m

rock

=

m

final

−

m

initial

=

250

l

g

−

120

l

g

=

130

l

g

−−−−−

The initial volume of water in the graduated cylinder was

30

mL

, and the volume after the rock was added read

75

mL

, so the rock's volume is

V

rock

=

V

final

−

V

initial

=

75

l

mL

−

30

l

mL

=

45

l

mL

−−−−−−

The equation for the density of the rock is

density

=

mass

volume

And so we have

density

=

130

l

g

45

l

mL

=

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

∣

2.9

l

g/mL

=

2.9

l

g/cm

3

∣

∣

∣

−−−−−−−−−−−−−−−−−−−−−−−−−

I hope this will help you

If helpful then please select my answer as brainliest answer

And also follow me ❤️ ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️

Answer 2

The density of the rock is 2.89 g/mL

Explanation:

We are given:

Mass of graduated cylinder, $m_1$ = 120 g

Mass of graduated cylinder + rock, $m_2$ = 250 g

Mass of rock, M = $m_2-m_1=(250-120)g=130g$

Volume of graduated cylinder, $v_1$ = 30 mL

Volume of graduated cylinder + rock, $v_2$ = 75 mL

Volume of rock, M = $v_2-v_1=(75-30)mL=45mL$

To calculate the density of substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Mass of rock = 130 g

Volume of rock = 45 mL

Putting values in above equation, we get:

$\text{Density of rock}=\frac{130g}{45mL}\\\\\text{Density of rock}=2.89g/mL$

Learn more about density:

https://brainly.com/question/3753959

https://brainly.com/question/13831570

#learnwithbrainly