a graduated cylinder has a mass of 83 g when empty. 20 mL of water is added. if a stone is added to the graduated cylinder, the water level rises to 36 mL and the total mass is now 144g. What is the density.
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We're asked to find the density of the rock, given some mass and volume information.
We're given that the mass of the system beforethe rock was added was 120 g. The mass afterthe rock was added was 250 g, so the rock's mass is
mrock=mfinal−minitial=250lg−120lg=130lg−−−−−
The initial volume of water in the graduated cylinder was 30 mL, and the volume after the rock was added read 75 mL, so the rock's volume is
Vrock=Vfinal−Vinitial=75lmL−30lmL=45lmL−−−−−−
The equation for the density of the rock is
density=massvolume
And so we have
density=130lg45lmL=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯∣∣∣ 2.9lg/mL=2.9lg/cm3 ∣∣∣−−−−−−−−−−−−−−−−−−−−−−−−−
rounded to 2 significant figures.
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We're given that the mass of the system beforethe rock was added was 120 g. The mass afterthe rock was added was 250 g, so the rock's mass is
mrock=mfinal−minitial=250lg−120lg=130lg−−−−−
The initial volume of water in the graduated cylinder was 30 mL, and the volume after the rock was added read 75 mL, so the rock's volume is
Vrock=Vfinal−Vinitial=75lmL−30lmL=45lmL−−−−−−
The equation for the density of the rock is
density=massvolume
And so we have
density=130lg45lmL=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯∣∣∣ 2.9lg/mL=2.9lg/cm3 ∣∣∣−−−−−−−−−−−−−−−−−−−−−−−−−
rounded to 2 significant figures.
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