A gramophone disc rotates at 60 rpm. A coin of mass 18 g is placed at a distance of 8 cm from the centre . Calculate the centrifugal force on the coin. Take pi-square= 9.87 .
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ang vel= w= 60rev/min
1 revolution= 2pi radian
one minute = 60 sec
w= 60*2pi/60
w= 2pi radian/sec
mass= 18g = 0.018 kg
distance =r= 8 cm = 0.08 m
f= mv^2/r
v=rw v^2=r^2w^2
f= mr^2w^2/r
r in divide will be removed by removing square
F= mrw^2
f= 0.018*0.08*(2pi)^2
square of 2 is 4
nd pi^2= 9.87 as per ur question
so:
0.018*0.08*4*9.87
= 0.05685
= 0.057.
1 revolution= 2pi radian
one minute = 60 sec
w= 60*2pi/60
w= 2pi radian/sec
mass= 18g = 0.018 kg
distance =r= 8 cm = 0.08 m
f= mv^2/r
v=rw v^2=r^2w^2
f= mr^2w^2/r
r in divide will be removed by removing square
F= mrw^2
f= 0.018*0.08*(2pi)^2
square of 2 is 4
nd pi^2= 9.87 as per ur question
so:
0.018*0.08*4*9.87
= 0.05685
= 0.057.
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