Question

A gramophone record turntable accelerate from rest to an angular velocity of 45.0rev/min in 1.60s its average angular acceleration

Answer 1

Answer:

SOLUTION..

ACCELERATION=F- I

T

45.-0÷ 1.60

28.125 Rad sec-²

Answer 2

answer:

∝ = 2.95 rad 5^-1

explanation:

Given that,

wi = 0 rad s^-1

wf = 45 revmin^-1

= 45 × 2π/60

= 4.712rad s^-1

t = 1.60s

∝ = ?

solution:

∝ = wf - wi/t

= 4.712 - 0/1.60

= 2.945 rad s^-2

∝ = 2.95 rad s^-2