Question

A graph is drawn with (1)/(u) along x-axis and (1)/(v) along the y-axis. If the intercept on the x-axis is 0.5 m^-1, the focal length of thr lens is (in meter).

Answer 1

Focal length of the lens = 2 meter  

Given:

A graph is drawn with $\frac{1}{u}$ along x-axis and $\frac{1}{v}$ along the y-axis. If the intercept on the x-axis is 0.5 $m^-^1$.

To find:

The focal length of the lens is (in meter).

Formula used:

   $\frac{1}{u}$ + $\frac{1}{v}$ = $\frac{1}{f}$

Explanation:

   $\frac{1}{u}$ + $\frac{1}{v}$ = $\frac{1}{f}$   ⇒    + $\frac{1}{v}$ = -  $\frac{1}{u}$ +  $\frac{1}{f}$    Because they given that y = $\frac{1}{v}$   comparing this equation from y= mx + c

The intercept on the x-axis is 0.5 $m^-^1$  so that y = o

That is 0 = - $\frac{1}{u}$ +  $\frac{1}{f}$

            $\frac{1}{f}$ = $\frac{1}{u}$

Given that  $\frac{1}{u}$ = 0.5

            $\frac{1}{f}$ = 0.5

   Focal length of the lens = 2 meter    

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