A graph of acceleration versus time of a particle starting
from rest at t = 0 is as shown in Fig. The speed of the particle
at t = 14 second is
(a) 2 ms⁻¹ (b) 34 ms⁻¹
(c) 20 ms⁻¹ (d) 42 ms⁻¹
Answers
Answered by
0
Answer:
I thought d option is the correct answer
Answered by
0
Answer:
Area under a−t graph is change in velocity
Area=
2
1
(4×4)+6×4+
2
1
×2×4−
2
1
×2×2
=36−2
=34m/s
As initial velocity is zero therefore, the velocity at 14 second is 34m/s
Similar questions