Question

A graph of pressure versus volume for an ideal gas for different processes is as shown in the graph
curve OC represents ​

Answer 1

We need to understand the slope of lines seen in adiabatic , isothermal , isobaric thermodynamic processes.

For Adiabatic Process :

$P {V}^{ \gamma } = constant$

$= > \dfrac{dP}{dV} {V}^{ \gamma } + P( \gamma {V}^{ \gamma - 1} ) = 0$

$= > \dfrac{dP}{dV} = - \gamma \dfrac{P}{V}$

For isothermal process : We follow the same process and we get :

$= > \dfrac{dP}{dV} = - \dfrac{P}{V}$

For isobaric process , the slope of P-V graph is zero.

$= > \dfrac{dP}{dV} = 0$

We know that $\gamma\: > 0$ , so slope of adiabatic curve will be greater than isothermal curve.

So OC curve represents Adiabatic Process.