A grasshopper can jump a maximum
horizontal distance of 40 cm. Its speed along
vertical direction will be
(2) 10 m/s
(1) 10√2 m/s
(3) V2 m/s
(4) 2√2 m/s
en laras
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Answer:
Range R = 40 cm jumping at Ф = 45° to the horizontal.
let g = 10 m/sec²
R = u² Sin2Ф / g
0.40 m = u² * 1 / g
u² = 4
u = 2 m/s
Horizontal component of speed = u cosФ = 2 * 1/√2 = √2 m/s
= 1.414 m/s
hope this helps you
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