Question

A green bulb and a red bulb are emitting radiation with equal power. The correct relation between number of photons emitted by the bulb per second is

Answer 1

The number of photons emitted by a red bulb and a blue bulb of equal power in a given time is given by

nr>nb

The formula for power generated by a photo is

P = nhf

• P is the power
• n is no of photons
• h is Planck's constant
• f is the frequency

Let the frequency of the photon released by red is fr and by blue bulb is fb.

As we know that the frequency of the red light is less than the frequency of blue

(fb>fr)

As per the the question Power is same from both the bulb so we can write

nrfrh=nbfbh

h cancels out both side so now ,

nr/nb=fb/fr

as fb/fr>1 ss nr/nb>1

so nr>nb

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