Question

A green bulb and a red bulb are emitting the radiations with equal power. The correct relation between numbers of photons emitted by the bulbs per second is

Answer 1

Answer:

it's simple as we know that p=ne/t where

p-power and n-no of photons

e-energy and T-time

also e=hc/lambda

where C-velocity of light and lambda-wavelength of light

so we finally get p=nhc/Lambda*t

and interchanging we get p*lambda=nhc/t

and as p,h,c are constant so we finally get

n/t α lambda

and we know red has more wavelength than green and so

it is no of photons emitted by bulbs per second emitted by red bulb is more than green bulb

HOPE IT HELPS