Question

a greeting cards is 8 cm long and 5 cm wide find the perimeter fast​

Answer 1

Given:-

• A greeting card is 8 cm long and 5 cm wide.

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To find:-

• Perimeter of a greeting card.

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Solution:-

Here,

• Length (l) = 8 cm
• Breadth (b) = 5 cm

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According to the question

We know that,

⇛ Perimeter = 2(length + breadth)

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→ P = 2(l + b)

→ P = 2(8 + 5)

→ P = 28(13)

→ P = 364 cm

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Hence,

• the perimeter of a greeting card is 364 cm.

Answer 2

Given :-

• Length of the greeting card = 8 cm
• Breadth ( Width ) of the  greeting card = 5 cm

To Find :-

• Perimeter of that greeting card

Solution :-

$\underline{\bf{\dag} \:\mathfrak{As\;we\;know\: that\: :}}$

★ Perimeter of a rectangle = 2 ( l + b )

Where ,

l is length

b is breadth

→ Let's find out by putting values in this formula

$\sf \mapsto 2 ( 8 \; cm + 5 \; cm )$

$\sf \mapsto 2 ( 13 \; cm )$

$\sf \mapsto 26 \; cm$

∴ Perimeter of the greeting card is 26 cm

More to know :-

✠ Perimeter of a square = 4 ( Side )

✠ Perimeter of a rectangle = 2 ( Length + Breadth )

✠ Perimeter of a Triangle = Sum of all Sides

✠ Perimeter of a Circle = 2πr

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