Math, asked by hvs9782828896, 9 months ago

A grey squirrel has 65 nuts gathered in its nest, and a red squirrel has 114 nuts gathered in its nest.A wily woodpecker steals nuts from both squirrels nests. It steals2/3as many nuts from the nest of thegrey squirrel as it steals from the nest of the red squirrel. After the woodpecker takes the nuts fromboth nests, the red squirrel has twice as many nuts left as the grey squirrel has. How many nuts does
the grey squirrel is left with?
(1) 33
(2) 36
(3) 48
(4) 30​

Answers

Answered by Swarup1998
8

Answer:

Option (1) = 33 is correct

The grey squirrel is left with 33 nuts.

Step-by-step explanation:

Given that the nuts collected by grey squirrel and red squirrel are 65 and 114 respectively.

Let the woodpecker steals x number of nuts from the red squirrel. Then it steals 2x/3 number of nuts from the grey squirrel.

Then nuts left with the grey squirrel is (65 - 2x/3) and that with the red squirrel is (114 - x)

By the given condition,

114 - x = 2 (65 - 2x/3)

or, 114 - x = 130 - 4x/3

or, 4x/3 - x = 130 - 114

or, x/3 = 16

or, x = 48

Therefore the number of nuts left with the grey squirrel is

= 65 - 2/3 (48) = 65 - 32 = 33

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