Question

A grinding wheel of mass 5.0 kg and diameter 0.20 m is rotating with an angular speed of 100 rad s-1. Calculate its kinetic energy. Through what distance would it have to be dropped in free fall to acquire this kinetic energy? ( Take g= 10.0 m s-2)

Answer 1

(1/2)Iw^2
= (1/2)(mr^2/2)(w^2) ....... w = omega
= (5×0.2×0.2×100×100)/4
= 500 J

now 1/2 mv^2 = 500
1/2×5×v^2 = 500
v = 10√2m/s

now by Newton's third law
v^2 - u^2 = 2as
200 - 0 = 2 × 10 × s
s = 10m

so this should be dropped upto 10m to get that much of kinetic energy.

plz mark that as BRAINLIEST
and hope it would be a BRAINLIEST answer!!
:)